Question

Find the equivalent resistance of the given circuit shown in figure.

• A. $20\Omega$
• B. $5\Omega$
• C. $8\Omega$
• D. $10\Omega$

Answer 1

The correct option is D $10\Omega$

The $12\Omega$ and $6\Omega$ resistors are in parallel, so their equivalent resistance is $R_1=12\times 6/(12+6)=4\Omega$.

The $7\Omega$ and $5\Omega$ resistors are in series, so their equivalent resistance is $R_2=7+5=12\Omega$.

The $R_1=4\Omega$ and $R_2=12\Omega$ are in parallel, so their equivalent resistance is $R_3=12\times 4/(12+4)=3\Omega$

Now this $R_3=3\Omega$ and $7\Omega$ are in series, so the equivalent resistance is $7+3=10\Omega$

So the equivalent resistance of circuit is $10\Omega$.