CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Find the four numbers in AP whose sum is 50 and in which the greatest number is 4 times the least .


Solution

Let the 4 no's be
a-3d , a-d , a+d , a+3d
then
a-3d+a-d+a+d+a+3d=50 
4a=50
a=25/2
but a+3d=4(a-3d)
a+3d=4a-12d
3a=15d
a=5d
25/2=5d
d=5/2 

so the 4 no's are

a-3d=25/2-15/2=10/2=5
a-d=25/2-5/2=20/2=10
a+d= 25/2+5/2=15
a+3d= 25/2+15/2=20
 

Mathematics

Suggest Corrections
thumbs-up
 
3


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image