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Question

Find the integral of the given function w.r.t x

y=sin 6x+10sec2xcosec xcot x



Solution

The correct option is A


y=sin 6x+10sec2xcosec xcot x

(sin 6x+10sec2xcosec xcot x)dx

(sin 6x)dx+(10sec2x)dx(cosec xcot x)dx

6x=t6dx=dtdx=dt6

(sin t)dt6+10tan x+c1(cosec x)+c2

cos(t)6+co+10tan x+c1+cosec x+c2

cos 6x6+10tan x+cosec x+c

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