Question

# Find the kinetic energy of $$5$$ liters of a gas at STP, given the standard pressure, is $$1.013 \times 10^5\, N/m^2$$.

Solution

## $$P=1.013 \times 10^5\, N/m^2,\,V=5\,litres=5 \times 10^{-3}\,m^3$$$$E=\dfrac{3}{2}PV$$$$=\dfrac{3}{2}(1.013 \times 10^5\, N/m^2)(5 \times 10^{-3}\,m^3)$$$$=7.5 \times 1.013 \times 10^2\,J$$$$=7.597 \times 10^2\,J$$This is the required energy.Physics

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