Question

Find the kinetic energy of $5$ liters of a gas at STP, given the standard pressure, is $1.013\times {10}^{5}N/m^2$.

Answer 1

$P=1.013\times {10}^{5}N/m^2,V=5litres=5\times {10}^{-3}{m}^3$
$E=\frac{3}{2}PV$
$=\frac{3}{2}(1.013\times {10}^{5}N/m^2)(5\times {10}^{-3}{m}^3)$
$=7.5\times 1.013\times {10}^{2}J$
$=7.597\times {10}^{2}J$
This is the required energy.