Question

Find the last 2 digits of the following number:
$65\times 29\times 37\times 63\times 71\times 87$

• A. 5
• B. 95
• C. 15
• D. 25

Answer 1

The correct option is B 95

$\frac{[65\times 29\times 37\times 63\times 71\times 87]}{100}\to \frac{[-35\times 29\times 37\times -37\times -29\times -13]}{100}\to \frac{[35\times 29\times 37\times 37\times 29\times 13]}{100}=\frac{[1015\times 1369\times 377]}{100}\to \frac{15\times 69\times 77}{100}\to$ remainder as 95.