CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the last two digit of 3400?

Open in App
Solution

We have, 3400=(32)200=9200=(101)200

=(10)200200C1(10)199+200C2(10)198200C3(10)197+...+200C198(10)2200C199(10)+1

=100μ200C199(10)+1 where μI

=100μ200C1(10)+1

=100μ2000+1

=100(μ20)+1

=100p+1 where p is an integer.

Hence, last two digits of 3400 is 00+1=01

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Measurement of Significant Figures
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon