Find the least number which when divided by 12 leaves a remainder of 7 ,when divided by 15 leaves a remainder of 10 and when divided by 16 leaves a remainder of 11.

(ANS given :235)

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Solution

12−7=5
15−10=5
16−11=5
Hence, the desired number is 5 short for divisibility by 12, 15 and 16.
L.C.M of 12, 15 and 16 is 240.
Hence, the least number=240−5=235

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Find the least number which when divided by 12 leaves a remainder of 7 ,when divided by 15 leaves a remainder of 10 and when divided by 16 leaves a remainder of 11. (ANS given :235)

12−7=5 15−10=5 16−11=5 Hence, the desired number is 5 short for divisibility by 12, 15 and 16. L.C.M of 12, 15 and 16 is 240. Hence, the least number=240−5=235 We found a similar question to the one that you posted. Please check it out here. LIKE IF SATISFIED

Find the least number which when divided by 12 leaves a remainder of 7 ,when divided by 15 leaves a remainder of 10 and when divided by 16 leaves a remainder of 11.

(ANS given :235)

12−7=5
15−10=5
16−11=5
Hence, the desired number is 5 short for divisibility by 12, 15 and 16.
L.C.M of 12, 15 and 16 is 240.
Hence, the least number=240−5=235

We found a similar question to the one that you posted. Please check it out here.

LIKE IF SATISFIED