Question

Find the least number which when divided by $20,18$ and $30$ gives the same remainder $9$ in each case.

• A. $179$
• B. $189$
• C. $169$
• D. $199$

Answer 1

The correct option is B $189$

Required number
$=(\text{L.C.M}$ of $20,18$ and $30)+9$
$=(2\times 5\times 3\times 2\times 3)+9$
$=180+9$
$=189$