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Question

Find the length of the diagonal of a square whose area is 128 cm2. Also, find its perimeter.

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Solution

Area of the square = 128 cm2
Area=12d2 (where d is a diagonal of the square)128=12d2d2=256d=16 cm

Now,
Area = Side2
128=Side2Side=11.31 cm

Perimeter = 4(Side)
=411.31=45.24 cm
Thus, the perimeter of the square is 45.24 cm.

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