Find the magnetic field due to a current carrying wire at point P- a-7 cm A- 2 - 10-7 TeslaB- 3 - 10-7 TeslaC- 10-5 TeslaD- 7 - 10-5 Tesla

The correct option is C 10^ 5 Tesla B = μ_0 i/4 π a (sin α + sin β) = 10^ 7× 5/7 × 10^ 2(sin α + sin β) =5/7× 10^ 5{4/5 + 3/5} = 7/5×5/7× 10^ 5 =10^ 5 T n ...

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Byju's Answer

Standard XII

Physics

Towards Biot-Savart Law

Find the magn...

Question

Find the magnetic field due to a current carrying wire at point P. (a =7 cm)

2 \times 10^{- 7}

Tesla

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3 \times 10^{- 7}

Tesla

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10^{- 5}

Tesla

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7 \times 10^{- 5}

Tesla

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Solution

The correct option is C $10^{- 5}$ Tesla

$B = \frac{μ_{0} i}{4 π a} (s i n α + s i n β)$
$= \frac{10^{- 7} \times 5}{7 \times 10^{- 2}} (s i n α + s i n β) = \frac{5}{7} \times 10^{- 5} {\frac{4}{5} + \frac{3}{5}} = \frac{7}{5} \times \frac{5}{7} \times 10^{- 5}$
$= 10^{- 5}$ T

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Q. Find the magnetic field due to a current carrying wire at point P. (a =7 cm)

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Find the magnetic field due to a current carrying wire at point P. (a =7 cm)

The correct option is C 10−5 Tesla B=μ0i4πa(sinα+sinβ) =10−7×57×10−2(sinα+sinβ)=57×10−5{45+35}=75×57×10−5 =10−5 T

The correct option is C $10^{- 5}$ Tesla

$B = \frac{μ_{0} i}{4 π a} (s i n α + s i n β)$
$= \frac{10^{- 7} \times 5}{7 \times 10^{- 2}} (s i n α + s i n β) = \frac{5}{7} \times 10^{- 5} {\frac{4}{5} + \frac{3}{5}} = \frac{7}{5} \times \frac{5}{7} \times 10^{- 5}$
$= 10^{- 5}$ T