Question

# Find the magnitude of electric field due to a dipole at a point P along the line joining point P and centre of dipole as shown in figure.

A
2.0×103 N/C
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B
3.5×103 N/C
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C
3.0×103 N/C
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D
2.5×103 N/C
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Solution

## The correct option is D 2.5×10−3 N/CGiven: Distance of charges from centre of dipole, l=1 mm Distance of point P from centre of dipole, x=5 m Magnitude of charge, q=10 nC=10×10−9 C Angle made of line joining of point P and centre of dipole with axis of dipole, θ=30∘ We know that the magnitude of an electric field at a point P far away (5 m>>1 mm) along the line joining of point P and centre of dipole due to a dipole is given by E=2kpcosθx3=4kqlcosθx3 ⇒E=4×9×109×10×10−9×1×10−3×cos30∘53 ⇒E=2.5×10−3 N/C Hence, option (d) is correct.

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