Question

Find the maximum power in the form of (10+x) which can be transmitted by means of a steel shaft rotating about its axis with an angular velocity $\omega =120rad/s$, if its length $l=200cm$, radius $r=1.50cm$, and the permissible torsion angle $\phi ={2.5}^{\circ }$. Round off to the nearest integer of x.

Answer 1

The maximum power that can be transmitted by means of a shaft rotating about its axis is clearly $N\omega$ where $N$ is the moment of the couple producing the maximum permissible torsion, $\phi$.
Thus $P=\frac{\pi r^{4}G\phi }{2l}\cdot \omega =16.9kw$