CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the mean of the following distribution.

Class100120120140140160160180180200Frequency10138712

A
149.2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
200
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
249.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 149.2
Class MarkFrequencyfx1101011001301316901508120017071190190122280
N=50
fx = 7460
Note that ¯¯¯x = fxN,
where ¯¯¯x stands for mean and N stands for the sum of frequencies.
Mean=746050=149.2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mean of a grouped data
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon