Find the mean of the following distribution by step-deviation method:
Daily expenditure (in Rs.) $100 - 150$ $150 - 200$ $200 - 250$ $250 - 300$ $300 - 350$
No. of households $4$ $5$ $12$ $2$ $2$

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Solution

$C . I$ $F r e q u e n c y$
$f_{i}$ $C l a s s - m a r k$
$x_{i}$ $x_{i} - A$ $u_{i} = \frac{x_{i} - A}{50}$ $f_{i} u_{i}$
$100 - 150$ $4$ $125$ $- 100$ $- 2$ $- 8$
$150 - 200$ $5$ $175$ $- 50$ $- 1$ $- 5$
$200 - 250$ $12$ $A = 225$ $0$ $0$ $0$
$250 - 300$ $2$ $275$ $50$ $1$ $2$
$300 - 350$ $2$ $325$ $100$ $2$ $4$
$\sum f_{i} = 25$ $\sum f_{i} u_{i} = - 7$
$\Rightarrow$ $M e a n = A + \frac{\sum f_{i} u_{i}}{\sum f_{i}} \times h$
$= 225 + \frac{(- 7)}{25} \times 50$
$= 225 - 14$
$= 211$

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25

Rs	$100 - 150$	$150 - 200$	$200 - 250$	$250 - 300$	$300 - 350$
Households	$4$	$5$	$12$	$2$	$2$

25

Daily expenditure (in C)	$100 - 150$	$150 - 200$	$200 - 250$	$250 - 300$	$300 - 350$
Number of households	$4$	$5$	$12$	$2$	$2$

The table below
shows the daily expenditure on food of 30 households in a locality

Daily expenditure (in Rs.)	$100 - 150$	$150 - 200$	$200 - 250$	$250 - 300$	$300 - 350$
No. of households	$6$	$7$	$12$	$3$	$2$

Find the mean and the median daily expenditure on food.

The table below shows the daily expenditure on food of 25 households in a locality.

Daily expenditure (in Rs)	100 − 150	150 − 200	200 − 250	250 − 300	300 − 350
Number of households	4	5	12	2	2

Find the mean daily expenditure on food by a suitable method.

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