Find the missing angle x andx-80- y-140-y-60-x -40-D- x-60- y-140-

The correct option is A x = 40^∘ y= 140^∘∠ ABE = ∠ DBC = 40^∘ [Vertically opposite angles] x = 40^∘ ∠ ABD = ∠ EBC = 140^∘ [Vertically opposite angles] ...

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Byju's Answer

Standard VI

Mathematics

Adjacent Angles

Find the miss...

Question

Find the missing angle x and y.

x =

40^{\circ}

140^{\circ}

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x =

80^{\circ}

140^{\circ}

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x =

40^{\circ}

60^{\circ}

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x =

60^{\circ}

140^{\circ}

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Solution

The correct option is A x = $40^{\circ}$ y= $140^{\circ}$
$∠ A B E = ∠ D B C = 40^{\circ}$ [Vertically opposite angles]
$x = 40^{\circ}$
$∠ A B D = ∠ E B C = 140^{\circ}$ [Vertically opposite angles]
$y = 140^{\circ}$

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Similar questions

Q. In Fig. 60, the values of x and y are
(a) x = 20, y = 130
(c) x = 20, y = 140
(b) x = 40, y = 140
(d) x = 15, y = 140

Consider the figure:

If BC = AC, x = 2y, and angle ∠ACB = 60^o, then find the value of ∠x & ∠y (in degrees).

Q. Mean life of following distribution in the following distribution is

57.6

hours. If sum of frequency is

50

then find the missing frequency

x

and

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$0 - 20$	$7$
$20 - 40$	$x$
$40 - 60$	$12$
$60 - 80$	$y$
$80 - 100$	$8$
$100 - 120$	$5$

Q. In the given figure, line PQ and line MN intersect at O. Determine the value of

y

when

x = 60 °

. Further, determine the value of

x

when

y = 40 °

Find the value of y, when x = 60 $^{0}$ in the figure below.

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Find the missing angle x and y.

The correct option is A x = 40∘ y= 140∘∠ABE=∠DBC=40∘ [Vertically opposite angles] x=40∘ ∠ABD=∠EBC=140∘ [Vertically opposite angles] y=140∘

The correct option is A x = $40^{\circ}$ y= $140^{\circ}$
$∠ A B E = ∠ D B C = 40^{\circ}$ [Vertically opposite angles]
$x = 40^{\circ}$
$∠ A B D = ∠ E B C = 140^{\circ}$ [Vertically opposite angles]
$y = 140^{\circ}$