Find the missing term:
3, 6, 24, 30, 63, 72, ?, 132

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120

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Solution

The correct option is C 120
$2^{2} - 1 = 4 - 1 = 3$
$3^{2} - 3 = 9 - 3 = 6$
$5^{2} - 1 = 25 - 1 = 24$
$6^{2} - 6 = 36 - 6 = 30$
$8^{2} - 1 = 64 - 1 = 63$
$9^{2} - 9 = 81 - 9 = 72$
So, the next term is $11^{2} - 1 = 121 - 1 = 120$
$12^{2} - 12 = 144 - 12 = 132$
So, the series is $3, 6, 24, 30, 63, 72, 120, 132$

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