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Question

Find the mode of the given data:

Class interval020204040606080Frequency1561810


Solution

As the class 40-60 has maximum frequency, so it is the modal class:

Therefore, 
xk=40, h=20, fk=18 and fk−1=6 and fk+1=10

Mode = (b) xk+h.{(fkfk1)(2fkfk1fk+1)}

  =40+[20×(18−6)/(2×18−6−10)]
  
   = 40+(12)
   = 52
 

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