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Moment of Force

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Question

Find the moment of force of 20 N about an axis of rotation at distance 0.5m from the force.

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Solution

F = 20 N ⊥ distance = 0.5 m
Moment of force = $F o r c e \times$ $p e r p e n d i c u l a r d i s t a n c e o f f o r c e f r o m t h e p o i n t o f r o t a t i o n$
= $F \times$ $⊥ d i s t a n c e$
= $20 N \times$ $0.5$ m
= 10 N m

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