Question

Find the multiplicative inverse of reciprocal of each of the following:

(i) 18
(ii) −16
(iii) $\frac{13}{25}$
(iv) $\frac{-17}{12}$
(v) $\frac{-6}{19}$
(vi) $\frac{-3}{-5}$
(vii) −1
(viii) 0

Answer 1

$$\begin{gathered} \begin{array}{l}\left(\text{i}\right)\text{Multiplicative inverse of 18}=\frac{1}{18}\\ \end{array} \\ \begin{array}{l}\text{ii})\text{Multiplicative inverse of}-\text{16}=\frac{-1}{16}\\ \end{array} \\ \begin{array}{l}\text{iii})\text{Multiplicative inverse of}\frac{13}{25}\\ \end{array}=\frac{25}{13} \\ \begin{array}{l}\text{iv})\text{Multiplicative inverse of}\frac{-17}{12}=\frac{12}{-17}\\ \end{array} \\ \begin{array}{l}\text{v})\text{Multiplicative inverse of}\frac{-6}{19}=\frac{19}{-6}\\ \end{array} \\ \begin{array}{l}\text{vi})\text{Multiplicative inverse of}\frac{-3}{-5}=\frac{-5}{-3}=\frac{5}{3}\\ \end{array} \\ \begin{array}{l}\text{vii})\text{Multiplicative inverse of}-1=\frac{1}{-1}=-1\\ \end{array} \\ \begin{array}{l}\text{viii})\text{Multiplicative inverse of}0=\frac{1}{0}=\text{infinity}\\ \\ \text{Hence, it does not exist}\text{.}\end{array} \end{gathered}$$