CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Find the n-factor in the following chemical changes :

$$C_2O^{2-}_4\rightarrow CO_2$$


A
1
loader
B
2
loader
C
3
loader
D
none of these
loader

Solution

The correct option is B 2
Given chemical change:
$$\mathrm{C}_{2}\mathrm{O}_{4}^{2-}\longrightarrow\mathrm{CO}_{2}$$
Here ,  oxidation state of $$C$$ in reactant is +3 while
that in product is +4 .
In this way, two carbons are going from +3 to +4 (oxidized),
hence, $$n-$$ factor $$=2$$
so correct option is B

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image