Question

# Find the n-factor in the following chemical changes :$$C_2O^{2-}_4\rightarrow CO_2$$

A
1
B
2
C
3
D
none of these

Solution

## The correct option is B 2Given chemical change:$$\mathrm{C}_{2}\mathrm{O}_{4}^{2-}\longrightarrow\mathrm{CO}_{2}$$Here ,  oxidation state of $$C$$ in reactant is +3 whilethat in product is +4 .In this way, two carbons are going from +3 to +4 (oxidized),hence, $$n-$$ factor $$=2$$so correct option is BChemistry

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