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Question

Find the n-factor of Cu in the following chemical changes.
(3Cu+8HNO3(dil)3Cu(NO3)2+4NO+2H2O)

A
2
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B
3
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C
1
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D
4
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Solution

The correct option is A 2
Steps for finding valency factor/n-factor:
1. Find the oxidation state (O.S.) of metal in reactant side.
2. Find the oxidation state of metal in product side.
3. Take the magnitude of difference of two oxidation state |O.S.ProductO.S.Reactant|×number of atom for the valency factor
(CuCu(NO3)2)
O.S. of Cu in product side
=x+2×(1)=0
x=+2
O.S. of Cu in reactant side
=2

valency factor=number of Cu atom×|O.S.ProductO.S.Reactant|
valency factor=1×|+20|
valency factor=2


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