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Question

Find the nth term of sequence 0, 3, 8, ...

A
n2 - 1
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B
n3 - 1
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C
2n2 - 2
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D
2n-1
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Solution

The correct option is A n2 - 1
T1 = 12 - 1 = 1 - 1 = 0 OR
= (1-1)×(1+1) = 0×2 = 0
T2 = 22 - 1 = 4 - 1 = 3 OR
= (2-1)×(2+1) = 1×3 = 3
T3 = 32 - 1 = 9 - 1 = 8 OR
= (3-1)×(3+1) = 2×4 = 8
thus
Tn = n2 - 1 OR
= (n-1)×(n+1) = n2 + n - n - 1 = n2 - 1

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