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Question

Find the nth term of sequence  0, 3, 8, ...


A
n2 - 1
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B
n3 - 1
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C
2n2 - 2
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D
2n-1
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Solution

The correct option is A n2 - 1
T1 = 12 - 1 = 1 - 1 = 0    OR
     = (1-1)×(1+1) = 0×2 = 0
T2 = 22 - 1 = 4 - 1 = 3    OR
     = (2-1)×(2+1) = 1×3 = 3
T3 = 32 - 1 = 9 - 1 = 8    OR
     = (3-1)×(3+1) = 2×4 = 8
thus 
Tn = n2 - 1    OR
     = (n-1)×(n+1) = n2 + n - n - 1 = n2 - 1

Mathematics

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