CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

Find the net electric field at an axial point P of a dipole as shown in figure.

A
1.50×103 N/C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.25×103 N/C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.88×103 N/C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.88×103 N/C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2.88×103 N/C
Given:
Distance of charges from centre of dipole, l=1 mm;

Distance of point P from centre of dipole, x=5.0015 m;

Magnitude of charge, q=10 nC;

Here, we can see that l<<x

Therefore, the net electric field due to a dipole at an axial point is given by

|Eax|=2k|p|x3=2k(q2l)x3=4kqlx3

|Eax|=4×9×109×10×109×1×10353

|Eax|=2.88×103 N/C

So, option (d) is correct.

flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image