Question

Find the no.of terms of a GP whose first term is 3/4, common ratio is 2 and last term is 384.

Answer 1

$$\begin{gathered} DearStudent, \\ {a}_{{}^n}=a{r}^{n-1} \\ \Rightarrow 384=\frac{3}{4}\times 2^{n-1} \\ \Rightarrow \frac{384\times 4}{3}=2^{n-1} \\ \Rightarrow 512=2^{n-1} \\ \Rightarrow 2^9=2^{n-1} \\ \Rightarrow 9=n-1 \\ \Rightarrow n=10 \\ Regards \end{gathered}$$