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Quantitative Aptitude

Number of Zeroes in a Number

Find the numb...

Question

Find the number of consecutive zeroes at the end of the following number.
77! $\times$ 42!

A

24

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B

9

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C

27

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D

18

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Solution

The correct option is C 27
The number of zeroes would depend on the number of 5's in the value of the factorial.
77! $\times$ 42! $\to$ 15 + 3 = 18 (for 77!) and 8 + 1 = 9 (for 42!).
Thus, the total number of zeroes in the given expression would be 18 + 9 = 27. Option (c) is correct.

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