Question

Find the number of degrees in each exterior exterior angle of a regular pentagon.

Answer 1

$$\begin{gathered} \mathrm{Each}\mathrm{exterior}\mathrm{angle}={\left(\frac{360}{\mathrm{n}}\right)}^{°} \\ \mathrm{For}\mathrm{a}\mathrm{regular}\mathrm{pentagon},n=5. \\ \therefore \mathrm{Exterior}\mathrm{angle}={\left(\frac{360}{5}\right)}^{°}=72° \end{gathered}$$