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Question

Find the number of electrons present in a pure sample of (NH4)2SO4 containing 8 moles of O-atoms?

A
6.43×1025
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B
8.43×1025
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C
5.34×1025
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D
8.34×1025
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Solution

The correct option is B 8.43×1025
From the formula unit of (NH4)2SO4, 4 moles of O-atoms are present in 1 mole of (NH4)2SO4.

Therefore, 8 moles of O-atomes will be present in
=84 moles of (NH4)2SO4

Again, the total number of electrons in one formula unit of (NH4)2SO4
=7×2+8×1+16+8×4=70

So, the total number of electrons in one mole of (NH4)2SO4
=70×6.022×1023

Therefore, the total number of electrons in 84 moles of (NH4)2SO4
=70×6.022×1023×2=8.43×1025

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