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Question

Find the number of positive real roots for equation 3 x5 - 4 x4 - 42 x3 + 56 x2 + 27x - 36 = 0. If all the roots of above given equation are real.


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Solution

Solution: Let f(x) = 3 x5 - 4 x4 - 42 x3 + 56 x2 + 27x - 36

According to Descartes' rule of signs

Total number of positive real roots = No. of charges in the sign occurs at any particular terms.

f(x) = 3 x5 - 4 x4 - 42 x3 + 56 x2 + 27x - 36

+ - - + + -

Change Change Change

No. of positive real roots = 3.


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