Question

# Find the number of sides of a regular polygon whose each exterior angles has a measure of $$72^{\circ}$$

Solution

## Let us assume the number of sides of the regular polygon be $$n$$,Sum of all exterior angles is $$360^o$$.\begin{aligned}\text { Then, } n =\dfrac{360^{\circ}}{ 72^{\circ}} \\n =5\end{aligned}Therefore, the number of sides of a regular polygon is $$5$$Mathematics

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