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Question

Find the number of sides of a regular polygon whose each exterior angles has a measure of
 $$ 72^{\circ} $$


Solution


Let us assume the number of sides of the regular polygon be $$ n $$,
Sum of all exterior angles is $$360^o$$.
$$\begin{aligned}\text { Then, } n =\dfrac{360^{\circ}}{  72^{\circ}} \\n =5\end{aligned}$$
Therefore, the number of sides of a regular polygon is $$5$$

Mathematics

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