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Question

Find the number of terms of the series 32, 24, 16, 8 ... for which the sum of the terms is zero.
  1. 7
  2. 8
  3. 10
  4. 6
  5. 9


Solution

The correct option is D 6

Soln:

Sn = [2a + (n -1) d]

0 = [64 – (n – 1)8]

n (72 – 8n) = 0

n = 9

So, number of terms required is 9. Hence (e)

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