Find the perimeter of a rectangle whose lenghth is 11/4 and breadth is 7/6

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Solution

$D e a r S t u d e n t L e n g t h = \frac{11}{4} b r e a d t h = \frac{7}{6} P e r i m e t e r = 2 (l + b) = 2 (\frac{11}{4} + \frac{7}{6}) = 2 (\frac{(11 \times 6) + (7 \times 4)}{(6 \times 4)}) = 2 (\frac{66 + 28}{24}) = 2 \times \frac{94}{24} = \frac{94}{12} = \frac{47}{6} u n i t R e g a r d s$

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