Question

Find the points where the graph of the equation 3x + 4y = 12 cuts the x-axis and the y-axis.

Answer 1

Given equation: $3x+4y=12$
or, $y=\frac{12-3x}{4}$
Now,
When $x=0$, then $y=\frac{12}{4}=3$

When $\text{x}=4$, then $y=\frac{0}{4}=0$

Thus, we have the following table:

$\text{x}$	0	4
$y$	3	0

Thus, the graph of the equation cuts the $\text{x}$-axis at (4, 0) and the $y$-axis at (0,3).