Question

# Find the potential drop across the capacitor C in the given circuit

A
0.2 V
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B
0.4 V
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C
0.8 V
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D
1.0 V
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Solution

## The correct option is B 0.4 VWhen capacitor is fully charged , the capacitor no current draws. So no current will pass in the capacitor branch and we can removed the branch from the circuit which is shown in figure.The equivalent resistance of the whole circuit is Req=0.4+(1+2)||(4+3)=0.4+3×73+7=0.4+2.1=2.5ΩThe current in the circuit is I=22.5=0.8AThe current through branch PAQ is I1=710I=(7/10)0.8=0.56A (by current division rule)The current through branch PAQ is I1=310I=(3/10)0.8=0.24AThus, VP−VA=1I1=0.56V....(1) and VP−VB=4I2=4(0.24)=0.96V....(2)(2)−(1)⇒VA−VB=0.96−0.56=0.4V . This is the potential across the capacitance.

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