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Question

Find the probability of getting $$53$$ fridays in a leap year.


A
17
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B
27
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C
37
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D
47
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Solution

The correct option is C $$\dfrac {2}{7}$$
There are 52 complete weeks and 366 days in a leap year.

there will be 2 extra days which can be any day of the week. 
For getting 53 Fridays, those days must be either fri sat or thur fri.

Total possibilities are 7.

Thus, probability = $$\dfrac{2}{7}$$

Maths

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