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Question

Find the product of 102×98 using appropriate identity

A
9996
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B
9906
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C
8996
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D
8096
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Solution

The correct option is A 9996
We know 102×98 = (100+2)(1002)
Using identity (x+y)(xy)=x2y2
Therefore, (100+2)(1002) =(100)2(2)2
=100004
=9996

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