Find the product of (a+b) and 7a2b2.
7a2b2
7a3b2+7a2b3
7a2b+7ab2
7a2b+7ab
a(b+c)=ab+ac (Distributive law) ⇒7a2b2×(a+b)
=(7a2b2×a) + (7a2b2×b)
=7a3b2+7a2b3
What is the product of (a+b) and 7a2b2?
Find 7ab-4bc+3ca, if a=2,b=-3 and c=5.