Find the product of $(2 x - 5 y)$ and $(3 x - 2 y)$

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Solution

$(2 x - 5 y) (3 x - 2 y)$
$= 2 x (3 x - 2 y) - 5 y (3 x - 2 y)$
$= 6 x^{2} - 4 x y - 15 x y + 10 y^{2}$
$= 6 x^{2} - 19 x y + 10 y^{2}$

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Similar questions

$\frac{F i r s t m o n o m i a l \to}{S e c o n d m o n o m i a l ↓}$	$2 x$	$- 5 y$	$3 x^{2}$	$- 4 x y$	$7 x^{2} y$	$- 9 x^{2} y^{2}$
$2 x$	$4 x^{2}$	.....	.....	.....	.....	.....
$- 5 y$	.....	.....	$- 15 x^{2} y$	.....	.....	.....
$3 x^{2}$	.....	.....	.....	.....	.....	.....
$- 4 x y$	.....	.....	.....	.....	.....	.....
$7 x^{2} y$	.....	.....	.....	.....	.....	.....
$- 9 x^{2} y^{2}$	.....	.....	.....	.....	.....	.....

2 x^{2} + 2 y^{2} = 3 x - 5 y + 7

$F i r s t m o n o m i a l \to - --------------- \to ↓ S e c o n d m o n o m i a l$	2x	-5y	$3 x^{2}$	-4xy	$7 x^{2} y$	$- 9 x^{2} y^{2}$
2x	$4 x^{2}$	-	-	-	-	-
- 5y	-	-	$- 15 x^{2} y$	-	-	-
$3 x^{2}$	-	-	-	-	-	-
- 4xy	-	-	-	-	-	-
$7 x^{2} y$	-	-	-	-	-	-
$- 9 x^{2} y^{2}$	-	-	-	-	-	-

The minimum value of 3x + 5y such that:

3 x + 5 y \leq 15

4 x + 9 y \leq 8

13 x + 2 y \leq 2

x \geq 0, y \geq 0

is ........................

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