Question

Find the product of the following:$(4x^2{y}^2-xy+3)\times \left(2x^{2}y\right)$

Answer 1

By distributive law,

$(4x^2{y}^2-xy+3)\times 2x^{2}y$ $=4x^2{y}^2\times 2x^{2}y-xy\times 2x^{2}y+3\times 2x^{2}y$ $=8x^4{y}^3-2x^3{y}^2+6x^{2}y$