CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the range of
f(x)=sinx1+tan2xcosx1+cot2x

A
[0,1]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
[1,0]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
[2,2]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
{0}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D {0}
f(x)=sinx1+tan2xcosx1+cot2x

f(x)=sinx1+tan2xcosx.tanx1+tan2x=0

Hence range of f(x) is {0}

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parametric Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon