CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the ratio between the energy stored in 5 μF capacitor to the 4 μF capacitor in the given circuit in steady state?
127131.png

Open in App
Solution

In steady state , the capacitors are fully charged and no current pass through them. So no current also pass through resistors 4 ohm and 5 ohm. Thus, the potential across the capacitors will be 2V.
Energy stored in 5μF capacitor is U5=12×5×22=10J
Energy stored in 4μF capacitor is U4=12×4×22=8J
Thus, U5/U4=10/8=5/4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon