CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the ratio in which the line segment joining the points (−3,10) and (6,−8) is divided by (−1,6)

A
1:7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2:7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2:5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3:7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2:7
Using the section formula, if a point (x,y) divides the line joining the points (x1,y1) and (x2,y2) in the ratio m:n, then (x,y)=(mx2+nx1m+n,my2+ny1m+n)
Let the ratio be k:1

Substituting (x1,y1)=(3,10) and (x2,y2)=(6,8) in the section
formula, we get (k(6)+1(3)k+1,k(8)+1(10)k+1)=(1,6)

(6k3k+1,8k+10k+1)=(1,6)

Comparing the x - coordinate,

6k3k+1=1
6k3=k1

7k=2

k=27

Hence, the ratio is 2:7


232558_239050_ans_42053defbb10488fb445fdd5034b3080.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Section Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon