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Question

Find the reading of the spring balance considering spring, pulley and string to be massless.


  1. 600 N
  2. 300 N
  3. 400 N
  4. 200 N


Solution

The correct option is B 300 N
The spring balance will read the tension in the string. Let the common acceleration is a.
FBD of the two blocks and the spring balance,

On applying F=ma on the two blocks and the spring, we get,
600T1=60a      .............(1)
T1T2=0            ............(2)
T2200=20a      .............(3)
On adding all the equations, we get,
a=5 m/s2, putting this in (1), we get,
T1=300 N
T1=T2=300 N        [from (2)]

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