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Question

Find the real values of x and y for which .
(1+i)y2+(6+i)=(2+i)x

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Solution

Given, (1+i)y2+(6+i)=(2+i)x
(y2+62x)+(y2x+1)i=0y2+62x=0,y2x+1=0
y22x=6 and y2x=1
On subtracting, we get x=5.
y25=1y2=4y=±2

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