Find the reciprocal of - 122 - 143 - - 23

K=[(12^2) (14^3)]× 2^3 We need to find 1K. K=[(12^2) (12^2)^3]× 2^3 K=[2^32^2 2^32^6] K=158⇒1/k=8/15 ∴reciprocal of[(1/2)^2 (1/4) ...

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Standard X

Mathematics

Properties of GP

Find the reci...

Question

Find the reciprocal of $[{(\frac{1}{2})}^{2} - {(\frac{1}{4})}^{3}] \times 2^{3}$

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Solution

$K = [({\frac{1}{2}}^{2}) - ({\frac{1}{4}}^{3})] \times 2^{3}$
We need to find $\frac{1}{K} .$
$K = [({\frac{1}{2}}^{2}) - (\frac{1}{2^{2}})^{3}] \times 2^{3}$
$K = [\frac{2^{3}}{2^{2}} - \frac{2^{3}}{2^{6}}]$
$K = \frac{15}{8} \Rightarrow \frac{1}{k} = \frac{8}{15}$
$∴ r e c i p r o c a l o f [(\frac{1}{2})^{2} - (\frac{1}{4})^{3}] \times 2^{3} i s \frac{8}{15}$

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Find the reciprocal of [(12)2−(14)3]×23

K=[(122)−(143)]×23We need to find 1K.K=[(122)−(122)3]×23K=[2322−2326]K=158⇒1k=815∴reciprocalof[(12)2−(14)3]×23is815

Find the reciprocal of $[{(\frac{1}{2})}^{2} - {(\frac{1}{4})}^{3}] \times 2^{3}$