Find the remainder obtained when $6 y^{5} + 30 y^{4} + 18 y^{3} + 6 y^{2} + 15 y + 3$ is divided by $2 y^{3} + 1$ . $[3 M a r k s]$

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Solution

$[2 M a r k s]$

Hence the remainder obtained is $3 y^{2} - 6$ . $[1 M a r k]$

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Similar questions

The remainder obtained when $6 y^{5} + 30 y^{4} + 18 y^{3} + 6 y^{2} + 15 y + 3$ is divided by $2 y^{3} + 1$ is $3 y^{2} - 6$ .

6 y^{5} + 30 y^{4} + 18 y^{3} + 6 y^{2} + 15 y + 3

2 y^{3} + 1

30 y^{4} + 11 y^{3} - 42 y^{2} + 3

3 y^{2} + 2 y

y^{2} + 7 y - 5

y + 3

30 y^{4} + 11 y^{3} - 42 y^{2} + 24 y + 3

3 y^{2} + 2 y

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