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Question

Find the remainder when $$1! + 2! + 3! + 4! + 5! + .... + 100!$$ is divided by 24 .


Solution

We have to find the remainder when $$1!+2!+3!+……..+100!$$ is divided by $$24$$.

$$1!+2!+3!+…….+100!=1+2+6+24+$$(multiply of $$24$$) then when it is divided 

by $$24$$, we get remainder as $$1+2+6=9$$.

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