Question

Find the remainder when ${30}^{{72}^{87}}$ is divided by 11.

• A. 5
• B. 9
• C. 6
• D. 3

Answer 1

The correct option is A 5

$\frac{{30}^{{72}^{87}}}{11}\to \frac{8^{{72}^{87}}}{11}=\frac{8^{10x}\times 8^{2^{87}}}{11}\to \frac{1\times 8^{2^{87}}}{11}\to \frac{8^{10x}\times 8^8}{11}\to Remainder=5$