Question

Find the root of the following quadratic equation
$6x^2-x-2=0$

Answer 1

$6x^2-x-2=0$

Here, $a=6,b=-1,c=2$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-(-1)\pm \sqrt{(-1{)}^2-4(6\left)\right(-2)}}{2\left(6\right)}$

$=\frac{1\pm \sqrt{1+48}}{12}$

$=\frac{1\pm \sqrt{49}}{12}$

$=\frac{1\pm 7}{12}$

$x=\frac{1+7}{12}$ and $x=\frac{1-7}{12}$

$\therefore$ $x=\frac{2}{3}$ and $x=\frac{-1}{2}$