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Question

Find the roots of  $$3x^2\,-\,11x\,+\,6\,=\,0$$


A
3,23
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B
3,23
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C
3,23
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D
3,23
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Solution

The correct option is A $$\displaystyle\,3,\,\frac{2}{3}$$
$$3x^2-11x+6=0$$
$$\therefore 3x^2-9x-2x+6=0$$
$$\therefore 3x(x-3)-2(x-3)=0$$
$$\therefore (3x-2)(x-3)=0$$
$$\therefore x=3$$ and $$x=\dfrac{2}{3}$$

Mathematics

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