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Question

Find the roots of the following quadratic equations by the factorization method.
32x25x2=0


Solution

Given equation is 32x25x2=0
32x2(6xx)2=0    [by splitting the middle term]
32x26x+x2=0
32x2322x+x2=0
32x(x2)+1(x2)=0
(x2)(32x+1)=0
Now, x2=0x=2
and 32x+1=0
x=132=26
Hence, the roots of the equation 32x25x2=0 are 26 and 2

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